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-5x^2+55x-120=0
a = -5; b = 55; c = -120;
Δ = b2-4ac
Δ = 552-4·(-5)·(-120)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-25}{2*-5}=\frac{-80}{-10} =+8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+25}{2*-5}=\frac{-30}{-10} =+3 $
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